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FAN5037M PDF预览

FAN5037M

更新时间: 2024-10-27 23:51:47
品牌 Logo 应用领域
飞兆/仙童 - FAIRCHILD 稳压器开关式稳压器或控制器模拟IC电源电路开关式控制器光电二极管栅极驱动
页数 文件大小 规格书
11页 103K
描述
Analog IC

FAN5037M 技术参数

是否Rohs认证: 符合生命周期:Obsolete
零件包装代码:SOIC包装说明:SOP, SOP8,.25
针数:8Reach Compliance Code:unknown
ECCN代码:EAR99HTS代码:8542.39.00.01
风险等级:5.66Is Samacsys:N
其他特性:ALSO REQUIRES A GATE DRIVE SUPPLY OF 9.5 TO 12.6模拟集成电路 - 其他类型:SWITCHING CONTROLLER
控制模式:CURRENT-MODE控制技术:PULSE WIDTH MODULATION
最大输入电压:5.25 V最小输入电压:4.75 V
标称输入电压:5 VJESD-30 代码:R-PDSO-G8
JESD-609代码:e3长度:4.9 mm
湿度敏感等级:1功能数量:1
端子数量:8最高工作温度:70 °C
最低工作温度:封装主体材料:PLASTIC/EPOXY
封装代码:SOP封装等效代码:SOP8,.25
封装形状:RECTANGULAR封装形式:SMALL OUTLINE
峰值回流温度(摄氏度):260认证状态:Not Qualified
座面最大高度:1.75 mm子类别:Switching Regulator or Controllers
表面贴装:YES切换器配置:SINGLE
温度等级:COMMERCIAL端子面层:Matte Tin (Sn)
端子形式:GULL WING端子节距:1.27 mm
端子位置:DUAL处于峰值回流温度下的最长时间:NOT SPECIFIED
宽度:3.9 mmBase Number Matches:1

FAN5037M 数据手册

 浏览型号FAN5037M的Datasheet PDF文件第4页浏览型号FAN5037M的Datasheet PDF文件第5页浏览型号FAN5037M的Datasheet PDF文件第6页浏览型号FAN5037M的Datasheet PDF文件第8页浏览型号FAN5037M的Datasheet PDF文件第9页浏览型号FAN5037M的Datasheet PDF文件第10页 
PRODUCT SPECIFICATION  
FAN5037  
charged and discharged through the enabling and disabling  
of the fixed current source. The variable current source is  
controlled from the error inputs that are received from the  
current and voltage feedback signals. The oscillator off-time  
is controlled by the amount of current that is available from  
the variable current source to charge the external capacitor up  
to the high threshold level of the comparator. The on-time is  
set by the constant current source that discharges the external  
capacitor voltage down to the lower comparator threshold.  
+5V  
+12V  
VCCA  
2
4
3
IFBL  
IFBH  
g
m
Constant On-Time Oscillator  
I
O
g
m
VCCP  
SDRV  
8
7
V
H
CEXT  
1
V
L
V
OUT  
I
ON  
REF  
FBSW  
5
6
GNDP  
65-5037-07  
Figure 2. FAN5037 Detailed Block Diagram  
Output Voltage Selection  
10  
0.4 – 0.42  
The FAN5037 precision reference is trimmed to be 1.2V  
nominally. When using the FAN5037, the system designer  
has complete flexibility in choosing the output voltage for  
one regulator from 1.2V to 3.6V. This is done by appropri-  
ately selecting the feedback resistors. These could be 0.1%  
resistors to realize optimum output accuracy. The following  
equations determines the output voltage of the regulator:  
*
No. Caps = ---------------------------------- = 2.44  
2
so that we need 3 input capacitors.  
Short Circuit Considerations  
The FAN5037 uses a current sensing scheme to limit the load  
current if an output fault condition occurs. The current sense  
resistor carries the peak current of the inductor, which is  
greater than the maximum load current due to ripple current  
flowing in the inductor. The FAN5037 will begin to limit the  
output current to the load by reducing the duty cycle of the  
top-side MOSFET driver when the voltage across the cur-  
rent-sense resistor exceeds the short circuit comparator  
R4 + R5  
R5  
(1)  
--------------------  
VOUT = 1.2 ×  
For example, for 3.3V:  
R4 + R5  
3.48k + 2.0k  
------------------------------  
2.0k  
--------------------  
VOUT = 1.2 ×  
= 1.2 ×  
= 3.3V  
R5  
threshold voltage (V ). When this happens the output volt-  
th  
Input Capacitors  
age will temporarily go out of regulation. As the voltage  
across the sense resistor becomes larger, the duty cycle of the  
top-side MOSFET will continue to be reduced until the cur-  
rent limit value is reached. At this point, the FAN5037 will  
continuously deliver the limit current at a reduced output  
voltage level. The short circuit comparator threshold voltage  
is typically 90mV, with a tolerance of ±10mV. The ripple  
current flowing through the inductor in Figure 1 is 0.6Apeak.  
Refer to Application Note AB-23 for detailed discussions.  
The sense resistor value can be approximated as follows:  
The number of input capacitors required for the FAN5037 is  
dependent on their ripple current rating, which assures their  
rated life. The number required may be determined by  
Iout DC – DC2  
*
(2)  
No. Caps = ---------------------------------------  
Irating  
where the duty cycle DC = (V +V  
) /V . For exam-  
in  
out f,diode  
ple, with a 1.5V output at 10A, 5V input, and using the  
Sanyo capacitors specified in Table 1 which have a 2A ripple  
current rating, we have DC = (1.5 + .5)/5 = 0.4, and  
Vth,min  
Vth,min  
----------------  
IPK  
---------------------------------------------  
0.6A + ILOAD,MAX  
RSENSE  
=
× (1 – TF) =  
× (1 – TF)  
(3)  
REV. 1.0.3 9/26/01  
7

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