AN273
If R is not installed, a resistive fault present between TIP and RING will provide enough loop current to cause the
SH
voltage on the TIP lead to drop. Since all of the loop current passes through the resistive fault, R , the equation
TR
for R becomes as follows:
TR
RST( VRING – VTIP
)
--------------------------------------------------------
=
RTR
1.5 + VTIP
Equation 5.
4.3. Condition 3: TIP to GND Fault
Resistive faults from TIP to GND are also detected in the TIP-OPEN linefeed state. In this case, the resistive fault
from TIP to GND (R ) reduces the longitudinal current through R (see Figure 4); thus, a more positive voltage is
TG
ST
present at the TIP terminal. Equation 6 describes R as a function of the TIP and RING voltages. Note that the
TG
denominator is the same as in the R calculation; so, the same critical voltage applies.
TR
1.5 V
TIP
RST
RSH
RTG
VOC
RSR
RING
Figure 4. TIP-OPEN Linefeed State with TIP to GND Resistive Fault
From the voltages measured at TIP and RING, the resistive fault from TIP to GND may be expressed as follows:
– VTIP × RST × RSH
-------------------------------------------------------------------------------------------------------------
=
RTG
RSH(1.5 + VTIP ) – RST( VRING – VTIP
)
Equation 6.
If R
is not installed, a gross measurement of the impedance from TIP-GND may be made in the FORWARD
SH
ACTIVE linefeed state. By applying a high common-mode voltage to TIP and keeping the differential voltage to 0 V
(V = 0), a resistive fault will form a voltage divider along with the 160 Ω output impedance of the TIP lead in the
OC
FORWARD ACTIVE state (see Figure 5).
Rev. 0.1
5