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CALCULATING

更新时间: 2024-11-27 23:39:27
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Calculating Transient Energy (59k)

CALCULATING 数据手册

  
SI97-02  
Surging Ideas  
TVS Diode Application Note  
PROTECTION PRODUCTS  
Calculating Transient Energy  
This application note explains how to calculate the  
transient energy which is absorbed by a suppression  
element. An approximation technique is employed for  
transient current impulse waveforms, assuming the  
clamping voltage is almost constant during the surge  
impulse.  
In the case of transients which are internal to the  
circuit, such as those created by inductive switching,  
the energy of the transient waveform may be readily  
calculated. Transients which are external to the circuit  
are more difficult to quantify. In this case an approxi-  
mation technique may then be used to estimate the  
energy which is absorbed by the suppression element.  
The energy which is absorbed by the suppression  
device is given by:  
tp  
VcIpdt  
E=  
= KVCLPtP  
0
Where  
E = Energy (Joules)  
Vc = Clamping Voltage (Volts)  
Ip = Peak Pulse Surge Current (Amps)  
tp = Impulse Duration  
K = Constant  
Figure 1 - Energy Waveforms/Form Factor Constants  
K values for the most common surge current wave-  
forms are given in Figure 1. For complex waveforms  
such as a double exponential impulse, the waveform  
may be divided into two parts to calculate the total  
energy.  
Example Calculation  
A typical waveform representative of lightning induced  
transients is shown in Figure 2. It is a 10/1000µs  
double exponential impulse as defined by Bellcore  
1089. To calculate the energy absorbed by an LC01-6  
first divide the waveform into two parts with part 1  
being the section of the waveform from 0 to 10µs and  
part two the section from the peak to 1000µs (the  
50% decay point). From the LC01-6 data sheet, the  
maximum clamping voltage at 100A is 15V.  
Therefore:  
Figure 2 - Double Exponential Impulse  
Waveform  
Part 1 : E1 = KVcIptp = 0.5*15*100*10x10-6 = 7.5mJ  
Part 2 : E2 = KVcIptp = 1.4*15*100*1x10-3 = 2.1J  
E = E1 + E2 = .0075 + 2.1 = 2.11J  
www.semtech.com  
Revision 9/2000  
1

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