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LM4870MX PDF预览

LM4870MX

更新时间: 2024-01-31 11:45:49
品牌 Logo 应用领域
美国国家半导体 - NSC 放大器功率放大器
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LM4870MX 数据手册

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put (Ri) resistor is 1.5:1. If Ri is set to the required input im-  
Application Information (Continued)  
=
pedance of 20 k, then Rf 30 k. The final design step is  
are required for 1.0W of output power. Since 5V rails are  
common, it is chosen to be the supply voltage. Supply volt-  
age (up to a maximum of 5.5V) above the required 4.6V will  
allow the LM4870 to reproduce transient signals at greater  
than 1.0W of output power. The extra voltage will also in-  
crease the device power dissipation, so the designer must  
make sure that the conditions explained in the Power Dissi-  
pationsection are not violated.  
to address the bandwidth requirements which must be  
stated as a pair of −3 dB frequency points. Five times away  
from a −3 dB point is 0.17 dB down from passband response  
±
which is better than the required 0.25 dB specified.  
=
=
fL 100 Hz/5 20 Hz  
=
=
fH 20 kHz5 100 HzAs stated in the External Compo-  
nents section, Ri in conjunction with Ci create a highpass  
filter.  
Once the power dissipation issues have been addressed,  
the required differential gain can be determined from Equa-  
tion 4:  
=
*
*
Ci 1/(2π 20 k20 Hz) 0.397 µF; use 0.39 µF.  
The high frequency pole is determined by the product of the  
desired high frequency pole, fH, and the differential gain, A  
=
=
=
vd. With a Avd 3 and fH 100 kHz, the resulting GBWP  
150 kHz which is much smaller than the LM4870 GBWP of  
4 MHz. This figure displays that if a designer has a need to  
design an amplifier with  
LM4870 can still be used without running into bandwidth  
problems.  
a higher differential gain, the  
=
=
2.83; use Avd  
From equation 4, the minimum Avd is A  
3.  
vd  
Since the amplifier output is bridged, giving a gain of 2, and  
the desired system gain is 3, the ratio of feedback (Rf) to in-  
7
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