Datasheet > AAT3221IGV-24-T1

AAT3221IGV-24-T1

更新时间： 2022-11-27 07:03:36

品牌	Logo	应用领域
ANALOGICTECH		稳压器
页数	文件大小	规格书
16页	392K
描述
150mA NanoPower⑩ LDO Linear Regulator

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AAT3221/2

150mA NanoPower™ LDO Linear Regulator

High Peak Output Current Applications

Device Duty Cycle vs. V_DROP

V_OUT= 2.5V @ 25 degrees C

Some applications require the LDO regulator to

operate at continuous nominal levels with short

duration high current peaks. The duty cycles for

both output current levels must be taken into

account. To do so, one would first need to calcu-

late the power dissipation at the nominal continu-

ous level, then factor in the addition power dissipa-

tion due to the short duration high current peaks.

3.5

200mA

2.5

1.5

For example, a 2.5V system using a AAT3221/

2IGV-2.5-T1 operates at a continuous 100mA load

current level and has short 150mA current peaks.

The current peak occurs for 378µs out of a 4.61ms

period. It will be assumed the input voltage is 5.0V.

0.5

100

Duty Cycle (%)

First, the current duty cycle percentage must be

calculated:

ꢀ Peak Duty Cycle: X/100 = 378ms/4.61ms

ꢀ Peak Duty Cycle = 8.2ꢀ

Device Duty Cycle vs. V_DROP

V_OUT= 2.5V @ 50 degrees C

The LDO Regulator will be under the 100mA load

for 91.8ꢀ of the 4.61ms period and have 150mA

peaks occurring for 8.2ꢀ of the time. Next, the

continuous nominal power dissipation for the

100mA load should be determined then multiplied

by the duty cycle to conclude the actual power dis-

sipation over time.

3.5

200mA

2.5

150mA

1.5

0.5

P_D(MAX)= (V_IN- V_OUT)I_OUT+ (V_INx I_GND

)

100

P_D(100mA)= (5.0V - 2.5V)100mA + (5.0V x 1.1mA)

P_D(100mA)= 250mW

Duty Cycle (%)

P_{D(91.8ꢀD/C)}= ꢀDC x P_D(100mA)

P_{D(91.8ꢀD/C)}= 0.918 x 250mW

P_{D(91.8ꢀD/C)}= 229.5mW

Device Duty Cycle vs. V_DROP

V_OUT= 2.5V @ 85 degrees C

3.5

100mA

2.5

200mA

150mA

1.5

0.5

100

Duty Cycle (%)

3221.2002.03.0.94

1...9 10 111213 14 15 16

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