Datasheet > AAT3218IGV-3.0-T1

AAT3218IGV-3.0-T1

更新时间： 2024-01-10 15:05:58

品牌	Logo	应用领域
ANALOGICTECH		/
页数	文件大小	规格书
18页	368K
描述
150mA MicroPower⑩ High Performance LDO

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AAT3218IGV-3.0-T1 技术参数

是否Rohs认证：	符合	生命周期：	Obsolete
包装说明：	,	Reach Compliance Code：	unknown
风险等级：	5.84	湿度敏感等级：	3
Base Number Matches：	1

AAT3218IGV-3.0-T1 数据手册

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AAT3218

150mA MicroPower™ High Performance LDO

High Peak Output Current Applications

Device Duty Cycle vs. V_DROP

(V_OUT= 2.5V @ 25°C)

Some applications require the LDO regulator to

operate at continuous nominal level with short dura-

tion, high-current peaks. The duty cycles for both

output current levels must be taken into account.

To do so, first calculate the power dissipation at the

nominal continuous level, then factor in the addi-

tional power dissipation due to the short duration,

high-current peaks.

3.5

2.5

200mA

1.5

0.5

For example, a 2.5V system using an AAT3218IGV-

2.5-T1 operates at a continuous 100mA load cur-

rent level and has short 150mA current peaks. The

current peak occurs for 378µs out of a 4.61ms peri-

od. It will be assumed the input voltage is 4.2V.

100

Duty Cycle (%)

First, the current duty cycle in percent must be

calculated:

Device Duty Cycle vs. V_DROP

(V_OUT= 2.5V @ 50°C)

% Peak Duty Cycle: X/100 = 378µs/4.61ms

% Peak Duty Cycle = 8.2%

3.5

The LDO regulator will be under the 100mA load

for 91.8% of the 4.61ms period and have 150mA

peaks occurring for 8.2% of the time. Next, the

continuous nominal power dissipation for the

100mA load should be determined then multiplied

by the duty cycle to conclude the actual power dis-

sipation over time.

2.5

200mA

1.5

150mA

0.5

100

Duty Cycle (%)

P_D(MAX)= (V_IN- V_OUT)I_OUT+ (V_INx I_GND

)

P_D(100mA)= (4.2V - 2.5V)100mA + (4.2V x 150µA)

P_D(100mA)= 170.6mW

Device Duty Cycle vs. V_DROP

(V_OUT= 2.5V @ 85°C)

P_D(91.8%D/C)= %DC x P_D(100mA)

P_D(91.8%D/C)= 0.918 x 170.6mW

P_D(91.8%D/C)= 156.6mW

3.5

100mA

2.5

The power dissipation for a 100mA load occurring

for 91.8% of the duty cycle will be 156.6mW. Now

the power dissipation for the remaining 8.2% of the

duty cycle at the 150mA load can be calculated:

200mA

150mA

1.5

0.5

100

P_D(MAX)= (V_IN- V_OUT)I_OUT+ (V_INx I_GND

P_D(150mA)= (4.2V - 2.5V)150mA + (4.2V x 150mA)

P_D(150mA)= 255.6mW

)

Duty Cycle (%)

P_D(8.2%D/C)= %DC x P_D(150mA)

P_D(8.2%D/C)= 0.082 x 255.6mW

P_D(8.2%D/C)= 21mW

3218.2006.04.1.8

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与AAT3218IGV-3.0-T1相关器件

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