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AAT3201IGV-2.0-T1 PDF预览

AAT3201IGV-2.0-T1

更新时间: 2024-02-25 20:25:39
品牌 Logo 应用领域
ANALOGICTECH 稳压器
页数 文件大小 规格书
14页 212K
描述
150mA OmniPower LDO Linear Regulator

AAT3201IGV-2.0-T1 技术参数

是否Rohs认证: 符合生命周期:Obsolete
包装说明:,Reach Compliance Code:unknown
风险等级:5.84湿度敏感等级:3
Base Number Matches:1

AAT3201IGV-2.0-T1 数据手册

 浏览型号AAT3201IGV-2.0-T1的Datasheet PDF文件第8页浏览型号AAT3201IGV-2.0-T1的Datasheet PDF文件第9页浏览型号AAT3201IGV-2.0-T1的Datasheet PDF文件第10页浏览型号AAT3201IGV-2.0-T1的Datasheet PDF文件第11页浏览型号AAT3201IGV-2.0-T1的Datasheet PDF文件第13页浏览型号AAT3201IGV-2.0-T1的Datasheet PDF文件第14页 
AAT3201  
150mA OmniPower™ LDO Linear Regulator  
High Peak Output Current Applications  
Device Duty Cycle vs. VDROP  
VOUT = 2.5V @ 25 degrees C  
Some applications require the LDO regulator to  
operate at continuous nominal levels with short  
duration high current peaks. The duty cycles for  
both output current levels must be taken into  
account. To do so, one would first need to calcu-  
3.5  
3
200mA  
2.5  
2
late the power dissipation at the nominal continu-  
ous level, then factor in the addition power dissipa-  
tion due to the short duration high current peaks.  
1.5  
1
0.5  
0
For example, a 2.5V system using a AAT3221/  
2IGV-2.5-T1 operates at a continuous 100mA load  
current level and has short 150mA current peaks.  
The current peak occurs for 378µs out of a 4.61ms  
period. It will be assumed the input voltage is 5.0V.  
0
10  
20  
30  
40  
50  
60  
70  
80  
90  
100  
Duty Cycle (%)  
First, the current duty cycle percentage must be  
calculated:  
% Peak Duty Cycle: X/100 = 378ms/4.61ms  
% Peak Duty Cycle = 8.2%  
Device Duty Cycle vs. VDROP  
VOUT = 2.5V @ 50 degrees C  
The LDO Regulator will be under the 100mA load  
for 91.8% of the 4.61ms period and have 150mA  
peaks occurring for 8.2% of the time. Next, the  
continuous nominal power dissipation for the  
100mA load should be determined then multiplied  
by the duty cycle to conclude the actual power dis-  
sipation over time.  
3.5  
3
200mA  
2.5  
2
150mA  
1.5  
1
0.5  
0
PD(MAX) = (VIN - VOUT)IOUT + (VIN x IGND  
)
0
10  
20  
30  
40  
50  
60  
70  
80  
90  
100  
PD(100mA) = (5.0V - 2.5V)100mA + (5.0V x 20µA)  
PD(100mA) = 250mW  
Duty Cycle (%)  
PD(91.8%D/C) = %DC x PD(100mA)  
PD(91.8%D/C) = 0.918 x 250mW  
PD(91.8%D/C) = 229.5mW  
Device Duty Cycle vs. VDROP  
VOUT = 2.5V @ 85 degrees C  
3.5  
3
100mA  
2.5  
2
200mA  
150mA  
1.5  
1
0.5  
0
0
10  
20  
30  
40  
50  
60  
70  
80  
90  
100  
Duty Cycle (%)  
12  
3201.2002.3.0.91  

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