5秒后页面跳转
73M1903-IM/F PDF预览

73M1903-IM/F

更新时间: 2024-02-29 00:38:58
品牌 Logo 应用领域
TERIDIAN 调制解调器
页数 文件大小 规格书
46页 530K
描述
Modem Analog Front End

73M1903-IM/F 技术参数

生命周期:Transferred包装说明:ROHS COMPLIANT, MO-153AC, TSSOP-20
Reach Compliance Code:unknown风险等级:5.59
商用集成电路类型:CONSUMER CIRCUITJESD-30 代码:R-PDSO-G20
长度:6.5 mm功能数量:1
端子数量:20最高工作温度:85 °C
最低工作温度:-40 °C封装主体材料:PLASTIC/EPOXY
封装代码:TSSOP封装形状:RECTANGULAR
封装形式:SMALL OUTLINE, THIN PROFILE, SHRINK PITCH认证状态:Not Qualified
座面最大高度:1.1 mm最大供电电压 (Vsup):3.6 V
最小供电电压 (Vsup):3 V表面贴装:YES
温度等级:INDUSTRIAL端子形式:GULL WING
端子节距:0.65 mm端子位置:DUAL
宽度:4.4 mmBase Number Matches:1

73M1903-IM/F 数据手册

 浏览型号73M1903-IM/F的Datasheet PDF文件第40页浏览型号73M1903-IM/F的Datasheet PDF文件第41页浏览型号73M1903-IM/F的Datasheet PDF文件第42页浏览型号73M1903-IM/F的Datasheet PDF文件第43页浏览型号73M1903-IM/F的Datasheet PDF文件第44页浏览型号73M1903-IM/F的Datasheet PDF文件第46页 
DS_1903_032  
73M1903 Data Sheet  
Example 3:  
Crystal Frequency = 27 MHz; Desired Sampling Rate, Fs = 7.2 kHz  
Step 1. First compute the required VCO frequency, Fvco, corresponding to  
Fs = 2.4 kHz x 3 = 7.2 kHz.  
Fvco = 2 x 2304 x Fs = 2 x 2304 x 2.4 kHz x 3 = 33.1776 MHz.  
Step 2. Express the required VCO frequency divided by the Crystal Frequency as a ratio of two integers.  
This is initially given by:  
2 2304 2.4kHz 3  
.
Fvco / Fxtal  
=
27MHz  
After a few rounds of simplification this reduces to:  
8
96  
5
Fvco/ Fxtal = (  
) (  
)
125  
Nnco1  
8
Dnco1  
Nnco2  
125  
5
=
=
Dnco2  
96  
The two ratios are not unique and many other possibilities exist. But for this particular application, they  
are found to be the best set of choices within the constraints of Prst and Nrst allowed. (Nnco1, Nnco2  
must be less than or equal to 8.)  
The ratio, Nnco1/Dnco1 = 8/125, is used to form a divide ratio for the NCO in prescaler and Nnco2/Dnco2  
=5/96 for the NCO in the PLL.  
Pre-scaler NCO: From Nnco1/Dnco1 = 8/125,  
Pdvsr = Integer [ Dnco1/Nnco1 ] = 15;  
Prst[2:0] = Nnco1 – 1 = 7;  
Dnco1/Nnco1 = 125/8 = 15.625 suggests a divide sequence of {÷16,÷16,÷15,÷16,÷16,÷15,÷16,÷15}, or  
Pseq = {1,1,0,1,1,0,1,0} = DAh.  
PLL NCO: From Nnco2/Dnco2 = 5/96,  
Ndvsr = Integer [ Dnco2/Nnco2 ] = 19;  
Nrst[2:0] = Nnco2 – 1 = 4;  
Dnco2/Nnco2 = 19.2 suggests a divide sequence of {÷19, ÷19, ÷19, ÷19, ÷20}, or  
Nseq = {x,x,x,0,0,0,0,1} = x1h.  
Rev. 2.0  
45  

与73M1903-IM/F相关器件

型号 品牌 描述 获取价格 数据表
73M1903-IMR/F TERIDIAN Modem Analog Front End

获取价格

73M1903-IVT/F TERIDIAN Modem Analog Front End

获取价格

73M1903-IVTR/F TERIDIAN Modem Analog Front End

获取价格

73M1922-IM/F MAXIM Consumer Circuit, 5 X 5 MM, ROHS COMPLIANT, QFN-32

获取价格

73M1922-IMR/F TERIDIAN Consumer Circuit, 5 X 5 MM, ROHS COMPLIANT, QFN-32

获取价格

73M1922-IMR/F MAXIM Consumer Circuit, 5 X 5 MM, ROHS COMPLIANT, QFN-32

获取价格