MC13150
Coilless Detector
voltage across the bandwidth resistor, R from Figure 12 is
B
V
R
– 2.44 Vdc = 0.56 Vdc for V
= 0.56V/1.0 µA = 560 kΩ. Actually the locking range will
= 3.0 Vdc, so
The quadrature detector is similar to a PLL. There is an
internal oscillator running at the IF frequency and two
detector outputs. One is used to deliver the audio signal and
the other one is filtered and used to tune the oscillator.
The oscillator frequency is set by an external resistor at
CC
B
CC
be ±13 kHz while the audio bandwidth will be approximately
±8.4 kHz due to an internal filter capacitor. This is verified in
Figure 13. For some applications it may be desirable that the
audio bandwidth is increased; this is done by reducing R .
Reducing R widens the detector bandwidth and improves
B
the F
pin. Figure 9 shows the control current required for a
particular frequency; Figure 10 shows the pin voltage at that
B
adj
the distortion at high input levels at the expense of 12 dB
SINAD sensitivity. The low frequency 3.0dB point is set by the
tuning circuit such that the product
current. From this the value of R is chosen. For example,
F
455 kHz would require a current of around 50 µA. The pin
voltage (Pin 16 in the 32 pin QFP package) is around 655mV
giving a resistor of 13.1 kΩ. Choosing 12 kΩ as the nearest
standard value gives a current of approximately 55 µA. The
R C = 0.68/f3dB.
T T
5.0 µA difference can be taken up by the tuning resistor, R .
So, for example, 150 k and 1.0 µF give a 3.0 dB point of
T
The best nominal frequency for the AFT
pin (Pin 17)
4.5 Hz. The recovered audio is set by R to give roughly
out
L
would be half supply. A supply voltage of 3.0 Vdc suggests a
resistor value of (1.5 – 0.655)V/5.0 µA = 169 kΩ. Choosing
150 kΩ would give a tuning current of 3/150 k = 20 µA. From
Figure 9 this would give a tuning range of roughly 10 kHz/µA
or ± 100 kHz which should be adequate.
50mV per kHz deviation per 100 k of resistance. The dc level
can be shifted by R from the nominal 0.68 V by the following
S
equation:
Detector DC Output = ((R + R )/R ) 0.68 Vdc
L
S
S
The bandwidth can be adjusted with the help of Figure 11.
For example, 1.0 µA would give a bandwidth of ± 13 kHz. The
Thus, R = R sets the output at 2 x 0.68 = 1.36 V;
S
L
R = 2R sets the output at 3 x 0.68 = 2.0 V.
L
S
Figure 12. BW
Current
adj
Voltage
Figure 13. Demodulator Output
versus Frequency
versus BW
adj
–3
10
10
0
V
= 3.0 Vdc
CC
= 25°C
T
A
–4
–5
–6
–7
R
= 560 k
10
10
10
10
B
–10
–20
–30
–40
–50
V
= 3.0 Vdc
= 25°C
= 50 MHz
= 50.455 MHz
R
= 1.0 M
CC
B
T
A
RF
LO
f
f
LO Level = –10 dBm
No IF Bandpass Filters
f
= ±4.0 kHz
dev
2.3
2.5
2.7
0.1
1.0
10
100
BW
VOLTAGE (Vdc)
f, FREQUENCY (kHz)
7
MOTOROLA ANALOG IC DEVICE DATA