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AD598A

更新时间: 2024-02-05 03:07:15
品牌 Logo 应用领域
亚德诺 - ADI 调节器
页数 文件大小 规格书
16页 555K
描述
LVDT Signal Conditioner

AD598A 技术参数

Source Url Status Check Date:2013-05-01 14:56:15.092是否无铅: 含铅
是否Rohs认证: 不符合生命周期:Obsolete
零件包装代码:SOIC包装说明:PLASTIC, SOIC-20
针数:20Reach Compliance Code:not_compliant
ECCN代码:EAR99HTS代码:8542.39.00.01
风险等级:8.76Is Samacsys:N
最大模拟输入电压:3.5 V转换器类型:SIGNAL CONDITIONER
JESD-30 代码:R-PDSO-G20JESD-609代码:e0
长度:12.8 mm湿度敏感等级:3
标称负供电电压:-15 V功能数量:1
端子数量:20最高工作温度:70 °C
最低工作温度:封装主体材料:PLASTIC/EPOXY
封装代码:SOP封装等效代码:SOP20,.4
封装形状:RECTANGULAR封装形式:SMALL OUTLINE
峰值回流温度(摄氏度):240电源:+-15 V
认证状态:Not Qualified座面最大高度:2.65 mm
信号/输出频率:20000 Hz子类别:Position Converters
最大压摆率:16 mA最大供电电压:36 V
最小供电电压:13 V标称供电电压:15 V
表面贴装:YES技术:BIPOLAR
温度等级:COMMERCIAL端子面层:Tin/Lead (Sn85Pb15)
端子形式:GULL WING端子节距:1.27 mm
端子位置:DUAL处于峰值回流温度下的最长时间:30
宽度:7.5 mmBase Number Matches:1

AD598A 数据手册

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AD598  
a voltage proportional to position. This technique uses the pri-  
mary excitation voltage as a phase reference to determine the  
polarity of the output voltage. There are a number of problems  
associated with this technique such as (1) producing a constant  
amplitude, constant frequency excitation signal, (2) compensating  
for LVDT primary to secondary phase shifts, and (3) compen-  
sating for these shifts as a function of temperature and frequency.  
As shown in Figure 6, the input to the integrator is [(A+B)d]B.  
Since the integrator input is forced to 0, the duty cycle d =  
B/(A+B).  
The output comparator which produces d = B/(A+B) also con-  
trols an output amplifier driven by a reference current. Duty  
cycle signals d and (1–d) perform separate modulations on the  
reference current as shown in Figure 6, which are summed. The  
summed current, which is the output current, is IREF × (1–2d).  
The AD598 eliminates all of these problems. The AD598 does  
not require a constant amplitude because it works on the ratio of  
the difference and sum of the LVDT output signals. A constant  
frequency signal is not necessary because the inputs are rectified  
and only the sine wave carrier magnitude is processed. There is  
no sensitivity to phase shift between the primary excitation and  
the LVDT outputs because synchronous detection is not em-  
ployed. The ratiometric principle upon which the AD598 oper-  
ates requires that the sum of the LVDT secondary voltages  
remains constant with LVDT stroke length. Although LVDT  
manufacturers generally do not specify the relationship between  
VA+VB and stroke length, it is recognized that some LVDTs do  
not meet this requirement. In these cases a nonlinearity will  
result. However, the majority of available LVDTs do in fact  
meet these requirements.  
Since d = B/(A+B), by substitution the output current equals  
I
REF × (A–B)/(A+B). This output current is then filtered and  
converted to a voltage since it is forced to flow through the scal-  
ing resistor R2 such that:  
VOUT = IREF ×( A B)/(A + B)× R2  
CONNECTING THE AD598  
The AD598 can easily be connected for dual or single supply  
operation as shown in Figures 7 and 12. The following general  
design procedures demonstrate how external component values  
are selected and can be used for any LVDT which meets AD598  
input/output criteria.  
Parameters which are set with external passive components in-  
clude: excitation frequency and amplitude, AD598 system  
bandwidth, and the scale factor (V/inch). Additionally, there are  
optional features, offset null adjustment, filtering, and signal in-  
tegration which can be used by adding external components.  
The AD598 utilizes a special decoder circuit. Referring to the  
block diagram and Figure 6 below, an implicit analog comput-  
ing loop is employed. After rectification, the A and B signals are  
multiplied by complementary duty cycle signals, d and (I–d)  
respectively. The difference of these processed signals is inte-  
grated and sampled by a comparator. It is the output of this  
comparator that defines the original duty cycle, d, which is fed  
back to the multipliers.  
V TO I  
INPUT  
A
FILT  
BINARY SIGNAL  
d
d - DUTY CYCLE  
0<d<1  
COMP  
±1  
INTEG  
COMP  
V TO I  
(A+B) d–B  
INPUT  
B
FILT  
1–d  
1–d  
B
A+B  
d
COMP  
±1  
VOLTS  
OUTPUT  
A–B  
IREF  
A+B  
IREF  
BANDGAP  
REFERENCE  
FILT  
INTEG  
d
V TO I  
RTO  
OFFSET  
A–B  
A+B  
VOUT  
= RSCALE x I REF  
x
Figure 6. Block Diagram of Decoder  
–5–  
REV. A  

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