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SP7652ERL/TR PDF预览

SP7652ERL/TR

更新时间: 2024-01-21 19:04:47
品牌 Logo 应用领域
西伯斯 - SIPEX 稳压器
页数 文件大小 规格书
16页 1269K
描述
Wide Input Voltage Range 6A, 600kHz, Buck Regulator

SP7652ERL/TR 技术参数

是否Rohs认证: 符合生命周期:Transferred
包装说明:7 X 4 MM, LEAD FREE, DFN-26Reach Compliance Code:unknown
风险等级:5.73其他特性:ALSO OPERATES WITH 3V TO 28V SUPPLY
模拟集成电路 - 其他类型:SWITCHING REGULATOR控制模式:VOLTAGE-MODE
控制技术:PULSE WIDTH MODULATION最大输入电压:5.5 V
最小输入电压:4.5 V标称输入电压:5 V
JESD-30 代码:R-PDSO-N26JESD-609代码:e3
长度:7 mm湿度敏感等级:3
功能数量:1端子数量:26
最高工作温度:85 °C最低工作温度:-40 °C
最大输出电流:10 A封装主体材料:PLASTIC/EPOXY
封装代码:HVSON封装等效代码:SOLCC26,.16,20
封装形状:RECTANGULAR封装形式:SMALL OUTLINE, HEAT SINK/SLUG, VERY THIN PROFILE
峰值回流温度(摄氏度):260认证状态:Not Qualified
座面最大高度:1 mm子类别:Switching Regulator or Controllers
表面贴装:YES切换器配置:BUCK
最大切换频率:720 kHz温度等级:INDUSTRIAL
端子面层:Matte Tin (Sn)端子形式:NO LEAD
端子节距:0.5 mm端子位置:DUAL
处于峰值回流温度下的最长时间:40宽度:4 mm
Base Number Matches:1

SP7652ERL/TR 数据手册

 浏览型号SP7652ERL/TR的Datasheet PDF文件第4页浏览型号SP7652ERL/TR的Datasheet PDF文件第5页浏览型号SP7652ERL/TR的Datasheet PDF文件第6页浏览型号SP7652ERL/TR的Datasheet PDF文件第8页浏览型号SP7652ERL/TR的Datasheet PDF文件第9页浏览型号SP7652ERL/TR的Datasheet PDF文件第10页 
APPLICATIONS INFORMATION  
Inductor Selection  
There are many factors to consider in  
selecting the inductor including core  
material, inductance vs. frequency, cur-  
rent handling capability, efficiency, size  
and EMI. In a typical SP7652 circuit, the  
inductor is chosen primarily by operat-  
ing frequency, saturation current and DC  
resistance. Increasing the inductor value  
will decrease output voltage ripple, but  
degrade transient response. Low induc-  
tor values provide the smallest size, but  
cause large ripple currents, poor efficiency  
and require more output capacitance to  
smooth out the larger ripple current. The  
inductor must be able to handle the peak  
current at the switching frequency without  
saturating, and the copper resistance in  
the winding should be kept as low as pos-  
sible to minimize resistive power loss. A  
good compromise between size, loss and  
cost is to set the inductor ripple current  
to be within 20% to 40% of the maximum  
output current.  
Ipp  
2
IpEak = iOut(max) +  
and provide low core loss at the high switch-  
ingfrequency.Lowcostpowdered-ironcores  
are inappropriate for 900kHz operation.  
Gappedferriteinductorsarewidelyavailable  
for consideration. Select devices that have  
operating data shown up to ꢀMHz. Ferrite  
materials, on the other hand, are more  
expensive and have an abrupt saturation  
characteristic with the inductance dropping  
sharply when the peak design current is  
exceeded. Nevertheless, they are preferred  
at high switching frequencies because they  
present very low core loss and the design  
only needs to prevent saturation. In general,  
ferrite or molypermalloy materials are bet-  
ter choice for all but the most cost sensitive  
applications.  
Optimizing Efficiency  
Thepowerdissipatedintheinductorisequal  
to the sum of the core and copper losses.  
To minimize copper losses, the winding  
resistance needs to be minimized, but this  
usually comes at the expense of a larger  
inductor.Corelosseshaveamoresignificant  
contribution at low output current where the  
copper losses are at a minimum, and can  
typically be neglected at higher output cur-  
rents where the copper losses dominate.  
Core loss information is usually available  
from the magnetics vendor. Proper inductor  
selection can affect the resulting power sup-  
ply efficiency by more than 15-20%!  
The switching frequency and the inductor  
operatingpointdeterminetheinductorvalue  
as follows:  
VOut(Vin(max) - VOut)  
L=  
Vin(max)FS•KRiOut(max)  
where:  
Fs = switching frequency  
KR = ratio of the AC inductor ripple current  
to the maximum output current  
The peak to peak inductor ripple current  
is:  
VOut (Vin(max) - VOut)  
The copper loss in the inductor can be cal-  
culated using the following equation:  
Ipp=  
Vin(max)Fs•L  
Pl(cu) = i2l(RmS) RWinDing  
Oncetherequiredinductorvalueisselected,  
theproperselectionofcorematerialisbased  
on peak inductor current and efficiency re-  
quirements. The core must be large enough  
not to saturate at the peak inductor current  
where IL(RMS) is the RMS inductor current  
that can be calculated as follows:  
2
Ipp  
3
Il(RmS) = iOut(max) 1+  
(IOut(max) )  
Rev F: ꢀꢀ/0ꢀ/06  
SP7652 Wide Input Voltage Range 6A, 600kHz, Buck Regulator  
© Copyright 2006 Sipex Corporation  
7

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