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73M1903C-IMR/F PDF预览

73M1903C-IMR/F

更新时间: 2024-01-21 18:28:13
品牌 Logo 应用领域
TERIDIAN 调制解调器消费电路商用集成电路
页数 文件大小 规格书
46页 452K
描述
Modem Analog Front End

73M1903C-IMR/F 技术参数

生命周期:Transferred包装说明:ROHS COMPLIANT, MO-153AC, TSSOP-20
Reach Compliance Code:unknown风险等级:5.59
商用集成电路类型:CONSUMER CIRCUITJESD-30 代码:R-PDSO-G20
长度:6.5 mm功能数量:1
端子数量:20最高工作温度:85 °C
最低工作温度:-40 °C封装主体材料:PLASTIC/EPOXY
封装代码:TSSOP封装形状:RECTANGULAR
封装形式:SMALL OUTLINE, THIN PROFILE, SHRINK PITCH认证状态:Not Qualified
座面最大高度:1.1 mm最大供电电压 (Vsup):3.6 V
最小供电电压 (Vsup):3 V表面贴装:YES
温度等级:INDUSTRIAL端子形式:GULL WING
端子节距:0.65 mm端子位置:DUAL
宽度:4.4 mmBase Number Matches:1

73M1903C-IMR/F 数据手册

 浏览型号73M1903C-IMR/F的Datasheet PDF文件第40页浏览型号73M1903C-IMR/F的Datasheet PDF文件第41页浏览型号73M1903C-IMR/F的Datasheet PDF文件第42页浏览型号73M1903C-IMR/F的Datasheet PDF文件第43页浏览型号73M1903C-IMR/F的Datasheet PDF文件第45页浏览型号73M1903C-IMR/F的Datasheet PDF文件第46页 
73M1903C  
Modem Analog Front End  
DATA SHEET  
After a few rounds of simplification this ratio reduces to:  
4
35  
18  
1
Fvco / Fxtal = (  
) (  
)
Nnco1  
4
Dnco1  
35  
=
=
Nnco2  
1
Dnco2  
18  
, where Nnco1 and Nnco2 must be < or equal to 8.  
The ratio, Nnco1/Dnco1 = 4/35, is used to form a divide ratio for the NCO in pre-scaler and Nnco2/Dnco2  
=1/18 for the NCO in the PLL.  
Pre-scaler NCO: From Nnco1/Dnco1 = 4/35,  
Pdvsr = Integer [ Dnco1/Nnco1 ] = 8;  
Prst[2:0] = Nnco1 – 1 = 3;  
Dnco1/Nnco1 = 35/4 = 8.75 suggests a divide sequence of {÷9,÷9,÷9,÷8}, or  
Pseq = {x,x,x,x,1,1,1,0} = xDh.  
PLL NCO: From Nnco2/Dnco2 = 1/18,  
Ndvsr = Integer [ Dnco2/Nnco2 ] = 18;  
Nrst[2:0] = Nnco2 – 1 = 0; this means NO fractional divide. It always does ÷18. Thus Pseq becomes  
“don’t care”.  
Nseq = {x,x,x,x,x,x,x,x} = xxh.  
Example3:  
Crystal Frequency = 27MHz; Desired Sampling Rate, Fs = 7.2kHz  
Step 1. First compute the required VCO frequency, Fvco, corresponding to  
Fs = 2.4kHz x 3 = 7.2kHz.  
Fvco = 2 x 2304 x Fs = 2 x 2304 x 2.4kHz x 3 = 33.1776MHz.  
Step 2. Express the required VCO frequency divided by the Crystal Frequency as a ratio of two integers.  
This is initially given by :  
223042.4kHz3  
.
Fvco/ Fxtal =  
27MHz  
After a few rounds of simplification this reduces to:  
8
125  
96  
5
Fvco / Fxtal = (  
) (  
)
.
Nnco1  
8
Dnco1  
125  
=
=
Nnco2  
5
Dnco2  
96  
The two ratios are not unique and many other possibilities exist. But for this particular application, they  
are found to be the best set of choices within the constraints of Prst and Nrst allowed. (Nnco1, Nnco2  
must be less than or equal to 8.)  
Page: 44 of 46  
© 2005-2008 TERIDIAN Semiconductor Corporation  
Rev 4.3  

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