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AN5369

更新时间： 2022-01-19 01:41:00

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Selection of SCRs for parallel operation

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AN5369 Application Note

AN5369

Selection Of SCRs For Parallel Operation

Application Note

Replaces September 2000 version AN5369-2.0

AN5369-2.1 July 2002

Selection of Thyristors (and Diodes) for Parallel Operation

with non-reactor/resistor sharing.

It is assumed here that all the variation in Forward Voltage Drop

between the thyristors is due to variation in the slope resistance

and that the knee voltage V₀is the same for both thyristors.

When thyristors are intended to be used in parallel without the

use of reactors or resistors to force current sharing then the

thyristors must be chosen in such a way that they will share the

current in relation to their forward voltage drop at the operating

current.

SCR₂is assumed to be the data book limit case device and V₀,

rt₂are the figures printed in the data book.

Now V₂= V₀+ I₁.rt₂for SCR₂

and V₂= V₀+ I₂.rt₁for SCR₁

i.e. I₁.rt₂= I₂.rt₁

This Application Note gives a simple way of doing this from the

data presented in the device data sheet, based on a number of

simplifying assumptions. The problems of differing turn-on

performance, finger voltage etc. have not been considered here

but are addressed in Application Note AN4999 “Turn-on

Performance of Thyristors in Parallel”. The treatise below is

presented in terms of the fully turned on phase of a thyristor

conduction cycle. The methodology can equally be applied to

rectifier diodes in parallel.

rt₁= I₁.rt₂/I₂..............................................................(1)

At the current I₁we have:

V₁= V₀+ I₁.rt₁

V₂= V₀+ I₁.rt₂

V₂-V₁= I₁.(rt₂-rt₁)

Dynex Semiconductor will append a 4 digit selection number to

the device type to specify your particular sharing criteria.

Substituting for rt₁from (1) we have

V₂-V₁= I₁.(rt₂- I₁.rt₂/I₂)

Consider the case of two thyristors in parallel with voltage V₂

across them. In this situation the total current is divided between

the two SCRs such that SCR₁is carrying I₂and SCR₂is carrying

I₁. At the current I₁SCR₁has a forward voltage drop of V₁.

i.e. ∆V = I₁.rt₂.(1 -I₁/I₂).......................................................(2)

SCR₁(V0, rT₁)

SCR₂(V0, rT₂)

I₂

I₁

Instantaneous forward volt drop - (V)

Fig. 1 Total current is divided between the two SCRs

1/4

www.dynexsemi.com

12 3

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